<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script language="JavaScript" type="text/javascript">
$(document).ready(function(){
$.ajax({
url: 'test.html',
cache: false,
success: function(html){
$("#result").html(html);
}
});
});
</script>
<title>JQuery</title>
</head>
<body>
<div id="result">тут должен появиться результат содержание файла test.html</div>
</body>
</html>